- Suppose a particle P rotating anticlockwise with radius A and angular frequency ω.
Of P, the displacement from the center of circle, the tangential velocity (ωA) and the centripetal
acceleration (ω2A) are represented, respectively, by the red, blue, and black vectors in the above figures.
- Suppose the displacement vector makes angle θ = ωt with the positive x-axis, so the projection of this vector on the y-axis is
y = Asinθ = A sin(ωt) ....(1)
- The tangential velocity leads the displacement by π/2, so the projection of the velocity vector on the y-axis is
vy =ωA sin(ωt + π/2) ....(2)
- The centripetal acceleration leads the displacement by π, so the projection of the acceleration vector on the y-axis is
ay =ω2Asin(ωt +π) ....(3)
- Using (1), (2) and the identity sin(θ + π) = -sinθ , we obtain ay = -ω2y, the SHM equation. Thus, we conclude
- A SHM can be regarded as an axis-projection of a uniform circular motion.
- In shm, the amplitudes of displacement, velocity and acceleration are A, ωA and ω2A respectively.
- Phase Differences: a leads v by π/2 ; v leads displacement by π/2.